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- A and B stand at distinct points of a circular race track of length 135 m. They cycle at a speed of a m/s and b m/s. They meet for the first time 5 secs after they start the race.
A and B stand at distinct points of a circular race track of length 135 m. They cycle at a speed of a m/s and b m/s. They meet for the first time 5 secs after they start the race.
Solve circular race track dynamics with distinct starting points and varying speeds. Discover how A and B's meeting times change with different initial directions.
by Maivizhi A
Updated Mar 18, 2024
A and B stand at distinct points of a circular race track of length 135 m. They cycle at a speed of a m/s and b m/s. They meet for the first time 5 secs after they start the race and for the second time 14 seconds from the time they start the race. Now if B had started in the opposite direction to the one he had originally started. They would have met for the first time after 60 seconds. If B is quicker then A, then find b?
b = 8 m/s.
Here's how
First Meeting after 5 seconds: When they meet for the first time after 5 seconds, the total distance covered by A and B combined is equal to the circumference of the circular track, which is 135 meters.
So, we have the equation:
"5a + 5b = 135" [since distance = speed × time]
Second Meeting after 14 seconds: When they meet for the second time after 14 seconds, A has covered one lap more than B. The difference in the distances covered by A and B in 14 seconds would be one lap.
So, we have the equation:
"14a - 14b = 135" [same logic as above]
Meeting after 60 seconds in opposite directions:
When they meet for the first time after 60 seconds while moving in opposite directions, the relative speed is the sum of their individual speeds.
So, we have the equation:
"60(a+b) = 135"
Now, we can solve these equations to find the value of 'b'.
From equation (1):
"5a + 5b = 135"
"a + b = 27"
From equation (2):
"14a - 14b = 135"
"a - b = 135/14"
Now, solving these two equations simultaneously:
"a + b = 27"
"a - b = 135/14"
Adding the two equations, we get:
"2a = 27 + 135/14"
"2a = (378 + 135)/14"
"2a = 513/14"
"a = 513/28"
Now, substituting the value of 'a' into equation (1):
"(513/28) + b = 27"
"b = 27 - (513/28)"
"b = (756 - 513)/28"
"b = 243/28"
Thus, "b = 243/28 ≈ 8.68" meters per second.
Time, Distance and Speed
Time, distance, and speed are interconnected concepts in physics and mathematics that are fundamental to understanding motion and travel. Here's a brief overview of each:
-
Time: Time is a measure of the duration between events. It's often denoted in units such as seconds, minutes, hours, days, etc. Time is a continuous and unidirectional dimension that flows uniformly forward (according to conventional understanding).
-
Distance: Distance is a measure of the length between two points. It can be measured in various units such as meters, kilometers, miles, etc. Distance is also a continuous dimension but is not inherently directional; it simply describes the extent of space between two objects or points.
-
Speed: Speed is a measure of how quickly an object moves through space. It's typically measured in distance units per unit of time, such as meters per second (m/s), kilometers per hour (km/h), miles per hour (mph), etc. Speed indicates the rate of change of distance with respect to time.
These concepts are related by the following formula:
Speed = Distance / Time
This formula can be rearranged to solve for any of the three variables if the other two are known.
- If you know the speed and the time, you can find the distance traveled using the formula: Distance = Speed * Time
- If you know the distance and the time, you can find the speed using the formula: Speed = Distance / Time
- If you know the distance and the speed, you can find the time using the formula: Time = Distance / Speed
Understanding these concepts and relationships is crucial for solving problems involving motion, such as calculating travel times, determining vehicle velocities, or estimating arrival times.
A and B stand at distinct points of a circular race track of length 135 m. They cycle at a speed of a m/s and b m/s. They meet for the first time 5 secs after they start the race and for the second time 14 seconds from the time they start the race - FAQs
1. What is the circular race track problem about?
The problem involves two cyclists, A and B, starting from different points on a circular track, meeting at various intervals, and determining their speeds.
2. How do we calculate the distance covered by A and B in the circular race track problem?
We use the formula: distance = speed × time. In this scenario, the total distance covered by A and B is equal to the circumference of the circular track.
3. What equations are derived from the first meeting of A and B?
The equation "5a + 5b = 135" is derived, representing the total distance covered by A and B in 5 seconds.
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